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Commit 98e5daa8 authored by Joel Cavat's avatar Joel Cavat
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Update corr

parent 1b3fd9dc
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...@@ -122,7 +122,7 @@ SELECT C.name, start_date, end_date, ...@@ -122,7 +122,7 @@ SELECT C.name, start_date, end_date,
FROM Conference AS C; FROM Conference AS C;
-- 15 -- 15
SELECT name, SUM(fees) AS total SELECT name, SUM(IFNULL(fees,0)) AS total
FROM Conference AS C FROM Conference AS C
LEFT JOIN Participation AS P ON C.id_conference = P.id_conference LEFT JOIN Participation AS P ON C.id_conference = P.id_conference
GROUP BY C.id_conference GROUP BY C.id_conference
...@@ -176,14 +176,29 @@ INNER JOIN Participation AS P ON C.id_conference = P.id_conference ...@@ -176,14 +176,29 @@ INNER JOIN Participation AS P ON C.id_conference = P.id_conference
WHERE login LIKE "stregunna14"; WHERE login LIKE "stregunna14";
-- 20 -- 20
SELECT S.login, firstname, lastname, fees SELECT DISTINCT S.login, firstname, lastname, fees
FROM Speaker AS S FROM Speaker AS S
INNER JOIN Participation AS P ON S.login = P.login INNER JOIN Participation AS P ON S.login = P.login
WHERE fees = ( WHERE fees = (
SELECT MAX(fees) FROM Participation SELECT MAX(fees) FROM Participation
); );
-- 21 -- 21
SELECT Speaker.login, firstname, lastname
FROM Speaker INNER JOIN Participation ON Speaker.login = Participation.login
GROUP BY Speaker.login
HAVING SUM(fees) = (SELECT MAX(SUM) FROM
(SELECT login, SUM(fees) AS SUM
FROM Participation
GROUP BY login));
SELECT S.login, firstname, lastname, SUM(fees) AS F SELECT S.login, firstname, lastname, SUM(fees) AS F
FROM Speaker AS S FROM Speaker AS S
INNER JOIN Participation AS P ON S.login = P.login INNER JOIN Participation AS P ON S.login = P.login
...@@ -194,6 +209,7 @@ HAVING F = ( ...@@ -194,6 +209,7 @@ HAVING F = (
) AS G ) AS G
); );
WITH GBY (login, firstname, lastname, sum) AS ( WITH GBY (login, firstname, lastname, sum) AS (
SELECT S.login, firstname, lastname, SUM(fees) AS F SELECT S.login, firstname, lastname, SUM(fees) AS F
FROM Speaker AS S FROM Speaker AS S
...@@ -227,7 +243,7 @@ WHERE login NOT IN ( ...@@ -227,7 +243,7 @@ WHERE login NOT IN (
); );
-- 24 -- 24
SELECT substr(A.lastname,1,2) AS SUB, A.firstname, A.lastname, B.firstname, B.lastname SELECT substr(A.lastname,1,2) AS SUB, A.login, A.firstname, A.lastname, B.login, B.firstname, B.lastname
FROM Visitor AS A FROM Visitor AS A
INNER JOIN Visitor AS B ON substr(A.lastname,1,2) = substr(B.lastname,1,2) INNER JOIN Visitor AS B ON substr(A.lastname,1,2) = substr(B.lastname,1,2)
WHERE A.login > B.login WHERE A.login > B.login
......
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