diff --git a/04_potentiel_electrique.md b/04_potentiel_electrique.md
index 2f56a2c3bd9337dbe3e3d1995e919be231834388..086ea61ca1af5d5c5bc973179d159bb0258f30d3 100644
--- a/04_potentiel_electrique.md
+++ b/04_potentiel_electrique.md
@@ -395,7 +395,7 @@ Les capacités sont représentées dans des circuits électriques pas un symbole
comme si la @fig:cap_symbol
{#fig:cap_symbol width=50%}
+électrique.](figs/cap_symbol.svg){#fig:cap_symbol width=20%}
Si on applique un voltage (un potentiel), $V$, entre les deux plaques en les
connectant à une batterie ou à une prise électrique par exemple, une des deux
@@ -435,11 +435,11 @@ $$
Exemple (Application de formules) #
-1. Calculer la capacité d'un condensateur donc les plaques rectangulaire ont
+1. Calculer la capacité d'un condensateur dont les plaques rectangulaire ont
des dimensions de $10\cm\times 5\cm$ et sont séparées d'une distance de
$1\mm$.
2. Quelle est la charge des plaques si on connecte la capacité à une batterie
- de $12\V$, quelle sera la charge des plaques?
+ de $12\V$?
3. Quelle est le champs électrique entre les plaques?
4. Quelle devrait être la distance entre les plaques pour avoir une capacité de
$1\F$?
@@ -454,7 +454,7 @@ Solution (Application de formules) #
peut en déduire la capacité via
\begin{equation}
C=\epsilon_0\frac{S}{d}=8.85\cdot 10^{-12}\frac{5\cdot
- 10^{-5}}{10^{-3}}=44.3\mathrm{pF}.
+ 10^{-3}}{10^{-3}}=44.3\mathrm{pF}.
\end{equation}
2. La charge des plaque est donnée par
$$
diff --git a/05_courant_electrique.md b/05_courant_electrique.md
index 3fa5baca1acd1c17f8c59d94b905deaf1bc9e3f2..3c09df4e2ea369c743cf617a6a430c6746380e3d 100644
--- a/05_courant_electrique.md
+++ b/05_courant_electrique.md
@@ -97,7 +97,7 @@ $$
$$
Nous savons que la charge élémentaire est $e=1.6\cdot 10^{-19}$. On a donc que
$$
-\frac{600}{e}\cong 4.4\cdot 10^{21}\mbox{ électrons}.
+\frac{750}{e}\cong 4.7\cdot 10^{21}\mbox{ électrons}.
$$
---
diff --git a/06_cicruits_electriques.md b/06_cicruits_electriques.md
index 49b08c79dfd2510ece31fdd48b4268d83f8fd004..432906d9f8b78359aa4d07b854edbb242f12e690 100644
--- a/06_cicruits_electriques.md
+++ b/06_cicruits_electriques.md
@@ -178,4 +178,80 @@ Exercice (Résistances multiples) #
Deux résistances de $100\Omega$ sont connectées en parallèle ou en série sur une batterie de $24\V$. Quel est le courant total dans chaque circuit? Et la résistance équivalente?
----
\ No newline at end of file
+---
+
+Pour des circuits beaucoup plus compliqués que ceux vus ici, il faut noter qu'il y a un ensemble
+de règles qu'on peut appliquer pour déterminer le courant dans un circuit: les **lois de Kirchoff**. On ne va pas les lister ou les étudier ici.
+
+## Les circuits contenant des capacités en parallèle ou en série
+
+Comme les résistances, les capacités peuvent être placée en série ou en parallèle.
+Pour le cas parallèle (voir @fig:three_cap_par) chaque capacité est soumise à la même
+différence de potentiel $V$. Ainsi les 3 capacités ont les charges
+$$
+Q_1=C_1 V,\quad Q_2=C_2 V,\quad Q_3=C_3 V.
+$$
+La conservation de la charge impose que la charge totale sortant de la source de tension
+est donnée par
+$$
+Q=Q_1+Q_2+Q_3.
+$$
+
+{#fig:three_cap_par width=50%}
+
+Si nous essayons de décrire ce circuit sous forme de circuit équivalent avec une seule capacité,
+$$
+Q=C_\mathrm{eq}V,
+$$
+on voit que
+\begin{align}
+C_\mathrm{eq}V&=Q_1+Q_2+Q_3,\nonumber
+C_\mathrm{eq}V&=(C_1+C_2+C_3)V,\nonumber
+C_\mathrm{eq}&=C_1+C_2+C_3.
+\end{align}
+
+Considérons maintenant le cas de capacités en série (voir @fig:three_cap).
+
+{#fig:three_cap width=50%}
+
+---
+
+Question (Capacité équivalente) #
+
+Déterminer la capacité équivalente des capacités branchées en série.
+
+Indication: Il faut évaluer $V$ en fonction des chutes de potentiel.
+
+---
+
+
+---
+
+Solution (Capacité équivalente) #
+
+Le voltage total au travers de toutes les capacités doit être donné par la somme des voltages au travers de chaque capacité
+$$
+V=V_1+V_2+V_3.
+$${#eq:tot_volt}
+On sait aussi que le charge est la même sur chaque capacité (conservation de la charge) et donc
+$$
+Q=C_1V_1=C_2V_2=C_3V_3.
+$$
+On peut réécrire @eq:tot_volt comme
+$$
+\frac{Q}{C_\mathrm{eq}}=\frac{Q}{C_1}+\frac{Q}{C_2}+\frac{Q}{C_3}=Q\left(\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}\right).
+$$
+
+---
+
+## Les circuits RC
+
+Souvent les capacités et résistances sont connectées en série dans les circuits électriques (voir @fig:rc). C'est même un composant essentiel
+dans quasiment tous les circuits du monde.
+Ces circuits sont particulièrement utiles quand
+les courant n'est pas stationnaire (qu'il dépend du temps). Dans cette section on va analyser les circuits RC dans certains cas particuliers.
+
+{#fig:rc width=50%}
+
+
+
diff --git a/figs/rc.svg b/figs/rc.svg
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