Put everything in its right place

serie2/rapport.md

@@ -5,6 +5,7 @@ As for part 2 of this work, we have largely solved everything on paper. This wor
 
 ### c)
 The calculation of the asymptotes are for -inf and +inf :
+
 $$
 \lim_{z \to -\infty} -ln(\frac{1}{1+e^{+z}})= \lim_{z \to -\infty} -ln(->0) = - (-\infty) = +\infty 
 $$